Integrand size = 24, antiderivative size = 232 \[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=-\frac {5 b d^3 m n x}{16 e^3}+\frac {3 b d^2 m n x^2}{32 e^2}-\frac {7 b d m n x^3}{144 e}+\frac {1}{32} b m n x^4+\frac {b d^3 n x \log \left (f x^m\right )}{4 e^3}-\frac {b d^2 n x^2 \log \left (f x^m\right )}{8 e^2}+\frac {b d n x^3 \log \left (f x^m\right )}{12 e}-\frac {1}{16} b n x^4 \log \left (f x^m\right )+\frac {b d^4 m n \log (d+e x)}{16 e^4}-\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {b d^4 n \log \left (f x^m\right ) \log \left (1+\frac {e x}{d}\right )}{4 e^4}-\frac {b d^4 m n \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{4 e^4} \]
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Time = 0.15 (sec) , antiderivative size = 232, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {2473, 45, 2393, 2332, 2341, 2354, 2438} \[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=-\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {b d^4 n \log \left (\frac {e x}{d}+1\right ) \log \left (f x^m\right )}{4 e^4}-\frac {b d^4 m n \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{4 e^4}+\frac {b d^4 m n \log (d+e x)}{16 e^4}+\frac {b d^3 n x \log \left (f x^m\right )}{4 e^3}-\frac {5 b d^3 m n x}{16 e^3}-\frac {b d^2 n x^2 \log \left (f x^m\right )}{8 e^2}+\frac {3 b d^2 m n x^2}{32 e^2}+\frac {b d n x^3 \log \left (f x^m\right )}{12 e}-\frac {7 b d m n x^3}{144 e}-\frac {1}{16} b n x^4 \log \left (f x^m\right )+\frac {1}{32} b m n x^4 \]
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Rule 45
Rule 2332
Rule 2341
Rule 2354
Rule 2393
Rule 2438
Rule 2473
Rubi steps \begin{align*} \text {integral}& = -\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {1}{4} (b e n) \int \frac {x^4 \log \left (f x^m\right )}{d+e x} \, dx+\frac {1}{16} (b e m n) \int \frac {x^4}{d+e x} \, dx \\ & = -\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {1}{4} (b e n) \int \left (-\frac {d^3 \log \left (f x^m\right )}{e^4}+\frac {d^2 x \log \left (f x^m\right )}{e^3}-\frac {d x^2 \log \left (f x^m\right )}{e^2}+\frac {x^3 \log \left (f x^m\right )}{e}+\frac {d^4 \log \left (f x^m\right )}{e^4 (d+e x)}\right ) \, dx+\frac {1}{16} (b e m n) \int \left (-\frac {d^3}{e^4}+\frac {d^2 x}{e^3}-\frac {d x^2}{e^2}+\frac {x^3}{e}+\frac {d^4}{e^4 (d+e x)}\right ) \, dx \\ & = -\frac {b d^3 m n x}{16 e^3}+\frac {b d^2 m n x^2}{32 e^2}-\frac {b d m n x^3}{48 e}+\frac {1}{64} b m n x^4+\frac {b d^4 m n \log (d+e x)}{16 e^4}-\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {1}{4} (b n) \int x^3 \log \left (f x^m\right ) \, dx+\frac {\left (b d^3 n\right ) \int \log \left (f x^m\right ) \, dx}{4 e^3}-\frac {\left (b d^4 n\right ) \int \frac {\log \left (f x^m\right )}{d+e x} \, dx}{4 e^3}-\frac {\left (b d^2 n\right ) \int x \log \left (f x^m\right ) \, dx}{4 e^2}+\frac {(b d n) \int x^2 \log \left (f x^m\right ) \, dx}{4 e} \\ & = -\frac {5 b d^3 m n x}{16 e^3}+\frac {3 b d^2 m n x^2}{32 e^2}-\frac {7 b d m n x^3}{144 e}+\frac {1}{32} b m n x^4+\frac {b d^3 n x \log \left (f x^m\right )}{4 e^3}-\frac {b d^2 n x^2 \log \left (f x^m\right )}{8 e^2}+\frac {b d n x^3 \log \left (f x^m\right )}{12 e}-\frac {1}{16} b n x^4 \log \left (f x^m\right )+\frac {b d^4 m n \log (d+e x)}{16 e^4}-\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {b d^4 n \log \left (f x^m\right ) \log \left (1+\frac {e x}{d}\right )}{4 e^4}+\frac {\left (b d^4 m n\right ) \int \frac {\log \left (1+\frac {e x}{d}\right )}{x} \, dx}{4 e^4} \\ & = -\frac {5 b d^3 m n x}{16 e^3}+\frac {3 b d^2 m n x^2}{32 e^2}-\frac {7 b d m n x^3}{144 e}+\frac {1}{32} b m n x^4+\frac {b d^3 n x \log \left (f x^m\right )}{4 e^3}-\frac {b d^2 n x^2 \log \left (f x^m\right )}{8 e^2}+\frac {b d n x^3 \log \left (f x^m\right )}{12 e}-\frac {1}{16} b n x^4 \log \left (f x^m\right )+\frac {b d^4 m n \log (d+e x)}{16 e^4}-\frac {1}{16} \left (m x^4-4 x^4 \log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {b d^4 n \log \left (f x^m\right ) \log \left (1+\frac {e x}{d}\right )}{4 e^4}-\frac {b d^4 m n \text {Li}_2\left (-\frac {e x}{d}\right )}{4 e^4} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 221, normalized size of antiderivative = 0.95 \[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {-6 \log \left (f x^m\right ) \left (-12 a e^4 x^4+b e n x \left (-12 d^3+6 d^2 e x-4 d e^2 x^2+3 e^3 x^3\right )+12 b d^4 n \log (d+e x)-12 b e^4 x^4 \log \left (c (d+e x)^n\right )\right )+m \left (-90 b d^3 e n x+27 b d^2 e^2 n x^2-14 b d e^3 n x^3-18 a e^4 x^4+9 b e^4 n x^4+18 b d^4 n (1+4 \log (x)) \log (d+e x)-18 b e^4 x^4 \log \left (c (d+e x)^n\right )-72 b d^4 n \log (x) \log \left (1+\frac {e x}{d}\right )\right )-72 b d^4 m n \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{288 e^4} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 78.15 (sec) , antiderivative size = 1180, normalized size of antiderivative = 5.09
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\[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=\int { {\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} x^{3} \log \left (f x^{m}\right ) \,d x } \]
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Timed out. \[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=\text {Timed out} \]
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Time = 0.23 (sec) , antiderivative size = 231, normalized size of antiderivative = 1.00 \[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {1}{288} \, {\left (\frac {72 \, {\left (\log \left (e x + d\right ) \log \left (-\frac {e x + d}{d} + 1\right ) + {\rm Li}_2\left (\frac {e x + d}{d}\right )\right )} b d^{4} n}{e^{4}} - \frac {18 \, b e^{4} x^{4} \log \left ({\left (e x + d\right )}^{n}\right ) + 14 \, b d e^{3} n x^{3} - 27 \, b d^{2} e^{2} n x^{2} + 90 \, b d^{3} e n x - 18 \, b d^{4} n \log \left (e x + d\right ) + 9 \, {\left (2 \, a e^{4} - {\left (e^{4} n - 2 \, e^{4} \log \left (c\right )\right )} b\right )} x^{4}}{e^{4}}\right )} m + \frac {1}{48} \, {\left (12 \, b x^{4} \log \left ({\left (e x + d\right )}^{n} c\right ) + 12 \, a x^{4} - b e n {\left (\frac {12 \, d^{4} \log \left (e x + d\right )}{e^{5}} + \frac {3 \, e^{3} x^{4} - 4 \, d e^{2} x^{3} + 6 \, d^{2} e x^{2} - 12 \, d^{3} x}{e^{4}}\right )}\right )} \log \left (f x^{m}\right ) \]
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\[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=\int { {\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} x^{3} \log \left (f x^{m}\right ) \,d x } \]
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Timed out. \[ \int x^3 \log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx=\int x^3\,\ln \left (f\,x^m\right )\,\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right ) \,d x \]
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